In this tutorial you will learn number pattern programs with there solutions. You can practice it to enhance your programming logic. I hope this exercises will help you to understand working of looping statements, if-else statements and more.
Quick links:
Ex: Write a C program to print number heart pattern, which shows the steps to print pattern. How to write a C program to print number heart pattern, which shows steps to print pattern . C program to print number heart pattern which shows steps to print pattern.
Input from user:
Enter the number: 5
Expected output:
11 22
1111 2222
333333333
3333333
33333
333
3
This pattern is same as previous exercises star heart pattern.
Only difference is:
In this pattern we only need to replace the * with numbers 1, 2 and 3.
This number's also shows the steps to print this pattern.
#include<stdio.h>
void main()
{
int no,z;
int i,j,k;
printf("Enter the number:\n");
scanf("%d",&no);
/*To print upper part*/
z=no*2;
for(i=no/2;i<=no;i=i+2)
{
/*To print left peak */
for(j=1;j<no-i;j=j+2)
{
printf(" ");
}
for(k=1;k<=i;k++)
{
printf("1");
}
/*To print right peak*/
for(j=1;j<=no-i;j++)
{
printf(" ");
}
for(k=1;k<=i;k++)
{
printf("2");
}
printf("\n");
}
/*To print lower part means inverted triangle*/
for(i=1;i<=no;i++)
{
for(j=1;j<i;j++)
{
printf(" ");
}
for(k=1;k<z;k++)
{
printf("3");
}
z-=2;
printf("\n");
}
}
Above program shows the following output:
Input from user:
Enter the number: 5
Expected output:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
For better understanding i have devided this code in two parts.
To print upper half part:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1. Accept input number from user.
2. Run outer for loop from 1 to no which shows rows in pattern:
for(i=1;i<=no;i++)
3. Run inner for loop from i to no-1 to print spaces:
for(j=i;j<no;j++)
{
printf(" ");
}
4. Run another inner for loop from 1 to i which shows columns in pattern:
for(k=1;k<=i;k++)
5. Inside the second inner for loop print value of k with one space:
printf("%d ",k);
6. After that outside the block of inner for loop print next line \n for print new row.
1 2 3 4
1 2 3
1 2
1
1. Run outer loop from 1 to no-1 which shows rows in pattern:
for(i=1;i<no;i++)
2. Run inner for loop from 1 to i to print spaces:
for(j=1;j<=i;j++)
{
printf(" ");
}
3. Run another one inner for loop from 1 to no-i and inside the loop print value of k :
for(k=1;k<=no-i;k++)
{
printf("%d ",k);
}
4. Last print \n for new row.
#include<stdio.h>
void main()
{
int no,i,j,k;
printf("Enter the number:");
scanf("%d",&no);
/*To print upper part*/
for(i=1;i<=no;i++)
{
for(j=i;j<no;j++)
{
printf(" ");
}
for(k=1;k<=i;k++)
{
printf("%d ",k);
}
/*For next row*/ printf("\n");
}
/*To print lower part*/
for(i=1;i<no;i++)
{
for(j=1;j<=i;j++)
{
printf(" ");
}
for(k=1;k<=no-i;k++)
{
printf("%d ",k);
}
/*For next row*/
printf("\n");
}
}
Above program shows the following output:
Input from user:
Enter the number: 5
Expected output:
1
123
12345
1234567
123456789
Input from user:
Enter the number:
5
Expected output:
12345
1234
123
12
1
1. Accept input number from user declare variable say no.
2. Run outer for loop from 1 to no which shows rows in pattern:
for(i=1;i<=no;i++)
3. Run inner for loop from 1 to (no+1)-i which shows columns in pattern:
for(j=1;j<=(no+1)-i;j++)
4. Inside the inner loop print value of j :
printf("%d",j);
5. For next row print \n.
#include<stdio.h>
void main()
{
int i,j,no;
printf("Enter the number:\n");
scanf("%d",&no);
/*Run outer loop from 1 to no*/
for(i=1;i<=no;i++)
{
/*Run inner loop from 1 to (no+1)-i*/
for(j=1;j<=(no+1)-i;j++)
{
/*Print value of j*/ printf("%d",j);
}
/*For next row*/ printf("\n");
}
}
Above program shows the following output:
Input from user:
Enter the number:
5
Expected output:
12345
1234
123
12
1
1. Accept input number from user declare variable say no.
2. Run outer for loop from 1 to no which shows number of rows:
for(i=1;i<=no;i++)
3. Run inner for loop from 1 to i-1 to print spaces:
for(j=1;j<i;j++)
{
printf(" ");
}
4. Run another one inner for loop from 1 to (no+1)-i to print star:
for(k=1;k<=(no+1)-i;k++)
{
printf("%d",k);
}
5. For next row print \n.
#include<stdio.h>
void main()
{
int i,j,k,no;
printf("Enter the number:\n");
scanf("%d",&no);
/*Run loops*/
for(i=1;i<=no;i++)
{
/* Print spaces from second row, in incremented manner*/
for(j=1;j<i;j++)
{
printf(" ");
}
/* Print numbers in decremented manner*/
for(k=1;k<=(no+1)-i;k++)
{
printf("%d",k);
}
/* For next row*/
printf("\n");
}
}
Above program shows the following output:
Input from user:
Enter the number: 5
Expected output:
1
12
123
1234
12345
This pattern is same as previous exercises star pattern:
*
**
***
****
*****
Difference is:
In this pattern we only need to replace the * with value of k .
1. Accept input number from user declare variable say no.
2. Run outer loop from 1 to no which shows the number of rows in pattern:
for(i=1;i<=no;i++)
3. Run first inner loop from i to no-1 to print spaces:
for(j=i;j<no;j++)
{
printf(" ");
}
4. Run second inner loop from 1 to i and print value of k:
for(k=1;k<=i;k++)
{
printf("%d",k);
}
5. For next row print \n.
#include<stdio.h>
void main()
{
int no,i,j,k;
printf("Enter the number:\n");
scanf("%d",&no);
/*Run loops*/
for(i=1;i<=no;i++)
{
for(j=i;j<no;j++)
{
/*Print spaces*/
printf(" ");
}
for(k=1;k<=i;k++)
{
/*Print value of k*/
printf("%d",k);
}
/*For new row*/ printf("\n");
}
}
Above program shows the following output:
Input from user:
Enter the number: 5
Expected output:
1
12
123
1234
12345
This pattern is same as previous exercises star pattern:
*
**
***
****
*****
Difference is:
In this pattern we only need to replace the * with value of j .
1. Accept input number from user declare variable say no.
2. Run outer for loop from 1 to no which shows rows in pattern:
for(i=1;i<=no;i++)
3. Run inner for loop from 1 to i which shows columns in pattern:
for(j=1;j<=i;j++)
4. Inside the inner loop print value of j :
printf("%d",j);
5. For next row print \n.
#include<stdio.h>
void main()
{
int no,i,j;
printf("Enter the number: ");
scanf("%d",&no);
/*Run outer loop from 1 to no*/
for(i=1;i<=no;i++)
{
for(j=1;j<=i;j++)
{
/*Print value of j*/ printf("%d",j);
}
/*For new row*/ printf("\n");
}
}
Above program shows the following output:
Input from user:
Enter the number: 5
Expected output:
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
Input from user:
Enter the number: 5
Expected output:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
This pattern is same as previous exercises star pyramid pattern:
*
**
***
****
*****
Difference is:
In this pattern we only need to replace the * with value of k .
1. Accept input number from user.
2. Run outer for loop from 1 to no which shows rows in pattern:
for(i=1;i<=no;i++)
3. Run inner for loop from i to no-1 to print spaces:
for(j=i;j<no;j++)
{
printf(" ");
}
4. Run another inner for loop from 1 to i which shows columns in pattern:
for(k=1;k<=i;k++)
5. Inside the second inner for loop print value of k with one space:
printf("%d ",k);
6. After that outside the block of inner for loop print next line \n for print new row.
#include<stdio.h>
void main()
{
int no,i,j,k;
printf("Enter the number:");
scanf("%d",&no);
for(i=1;i<=no;i++)
{
for(j=i;j<no;j++)
{
/*Print spaces*/
printf(" ");
}
for(k=1;k<=i;k++)
{
/*print value of k with one space...to print it like a pyramid*/
printf("%d ",k);
}
/*For next row*/
printf("\n");
}
}
Above program shows the following output:
