C program to print number between 1 to 10 in character format using switch-case

 Ex: write a C program to print  number between 1 to 10 in character formate. How to write a C program to print number between 1 to 10 in character format. C program to print number between 1 to 10 in character format.

Input from user:

Enter the number between 1 to 10:  5

Expected output:

You entered FIVE



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  Step by step logic of the given program:


1. Accept input (number) from user variable say no.

2. Switch the value of no using switch(no) and match with cases.

3. Inside the body of switch we will give 10 possible values of no  i.e. 1 to 10

4. Therefore we will write 10 cases inside the switch.

5. If any case does not matches then for default case print invalid number.



  C program to print  number between 1 to 10 in character format using switch-case:



#include<stdio.h>
void main()
{
int no;

printf("Enter the number between 1 to 10: ");
scanf("%d",&no);

switch(no)
{
case 1:
printf("You entered ONE");
break;
 
 case 2:
printf("You entered TWO");
 break;
 
 case 3:
printf("You entered THREE");
 break;
 
 case 4:
printf("You entered FOUR");
 break;
 
 case 5:
printf("You entered FIVE");
 break;
 
case 6:
printf("You entered SIX");
 break;
 
 case 7:
printf("You entered SEVEN");
 break;
 
 case 8:
printf("You entered EIGHT");
 break;

case 9:
printf("You entered NINE");
 break;

case 10:
printf("You entered TEN");
 break;
 
default:
printf("Invalid number");

}
}



Above program shows the following output:


C program to print  number between 1 to 10 in character format using switch-case

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